factor 1st then solve.
x/x-10 + 7/x-5 =x^2/x^2-15+50
2007-06-12 17:39:11 · 4 answers · asked by mecca laran 4 in Science & Mathematics ➔ Mathematics
x/x-10 + 7/x-5 =x^2/x^2-15+50
1 -10 +7/x -5 = 1 -15+50
-7/x = 50
x = -7/50
2007-06-12 17:43:19 · answer #1 · answered by sweet n simple 5 · 0⤊ 0⤋
so first combine like terms for both sides
x/x + 7/x + -10 - 5
=1(x/x=1) +7/x -15
=7/x-14
(first side)
x^2/x^2 -15 + 50
=1(x^2/x^2=1) + 35
=36
(second side)
so, it really is 7/x -14=36
add 14 to both sides to give you 7/x=50
times x for both sides which gives you 7=50x
then divide both sides by 50, and so your answer is
7/50.
2007-06-13 00:52:31 · answer #2 · answered by Anonymous · 0⤊ 0⤋
x/(x-10) + 7/(x-5) = x²/[(x-5)(x-10)]
multiply all by (x-5)(x-10), and eliminate denominators
x(x-5) + 7(x-10) = x²
x² - 5x + 7x - 70 = x²
2x = 70
x = 35
2007-06-13 00:45:13 · answer #3 · answered by Philo 7 · 0⤊ 0⤋
x/x-7T =pi - 7 squared 10 root -
I billion dollars
2007-06-13 00:46:59 · answer #4 · answered by banjaxed 6 · 0⤊ 0⤋