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2007-06-12 14:40:31 · 3 answers · asked by dorito 1 in Science & Mathematics Chemistry

the 3 salts:
Nacl
CaCl2
AlCl3

i think Nacl = low boiling point
AlCl3 = high " "

2007-06-12 14:51:32 · update #1

3 answers

No, both would raise the boiling point of a solution. NaCl would just affect it to a smaller degree as compared to AlCl3 due to the number of particles into which each dissociates. In plain english, NaCl breaks down into two ions, Na+ and Cl- while AlCl3 breaks down into four, Al3+ and 3 Cl-. This phenomenoa is due to the Van't Hoff Factor.

2007-06-12 14:47:08 · answer #1 · answered by Anonymous · 0 1

No, all three salts will elevate the boiling point, according to Raoult's Law. The salts dissolved in solution reduce the vapor pressure of the solution, thus increasing the temperature at which the solution boils, proportional to the total concentrations of all ions in solution.

If equal numbers of moles of the three compounds were dissolved in the same amount of water, the AlCl3 would raise the boiling point the most (generates four ions), CaCl2 somewhere in the middle (3 ions), and NaCl the least (only two ions).

2007-06-12 15:01:45 · answer #2 · answered by Dave_Stark 7 · 0 0

The more particles that you add, the more increase in boiling point you get. NaCl will come apart into Na+ and Cl-, 2 particles, AlCl3 will come apart into Al+3 and 3 Cl- ions, molar amounts of
AlCl3 will increase it more

2007-06-12 14:47:47 · answer #3 · answered by science teacher 7 · 1 0

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