Algebra last min question, need help fast thanks!!!!!!!!!!?

Question

14. Find the range for the function M(x) =
x2 -3x + 5 if the domain is D = {-2, 0, 1}.


A.
{3, 5, 15}

B.
{3, 5, 7}

C.
{-3, 0, 15}

D.
{-5, 3, 15}

15. Given the function P(z) = z2 - 8, find P(-2).


A.
4


B.
0

C.
-4

D.
-6

Answer 1

14. The range is the set of values that the function can spit out when you put in any of the values in the domain. So all we have to do is:
Plug in the three different values.
at -2: (-2)^2-3(-2)+5 = 4+6+5=15
at 0: (0)^2-3(0)+5=5
at 1: (1)^2-3(1)+5=1-3+5=3

So the range is {3,5,15}, answer A.


15. P(z) means what you get when you apply function P to any variable z. So simply plug in z = -2. You get
P(-2)=(-2)^2-8 = 4-8=-4, answer C.

Answer 2

For question 14, just plug in the three values of the domain into the function and you have the range!

For 15, (-2)^2-8 = 4-8 = -4

Answer 3

Question 14
M(-2) = 4 + 6 + 5 = 15
M(0) = 5
M(1) = 3
OPTION A

Question 15
P(-2) = 4 - 8 = - 4
OPTION C

Answer 4

14.

M(x) = x^2 -3x + 5
M(-2)=(-2)^2 - 3(-2) + 5
M(-2)=15

M(0)=(0)^2 - 3(0) + 5
M(0)=5

M(1)=(1)^2 - 3(1) + 5
M(1)=3

ans:A

15.

P(z) = z^2 - 8
P(-2) = (-2)^2 - 8
P(-2) = -4

ans:C