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2007-06-12 12:33:32 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

vertex is at (0,0) since (y-0)² = 12(x-0), and the 12 is 4 times the focal length. so, since the parabola is horizontal, opening right, focus is at (3,0).

2007-06-12 12:39:01 · answer #1 · answered by Philo 7 · 0 0

y^2 = 4px

12 = 4p
p = 3

the focus is at (3,0)

2007-06-12 19:43:20 · answer #2 · answered by      7 · 0 0

y^2=12x
y^2 = 2px so p = 6
The focus is at (p/2,0) = (3,0)

2007-06-12 19:40:19 · answer #3 · answered by ironduke8159 7 · 0 0

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