f (x) = 1
-------
square root x-6
***x-6 is under the square root sign
2007-06-12 12:28:50 · 4 answers · asked by Desilicious 1 in Science & Mathematics ➔ Mathematics
x > = 6
2007-06-12 12:31:38 · answer #1 · answered by richardwptljc 6 · 0⤊ 0⤋
Because you can't have a real number as a square root of a negitive number, so x-6 has to be =>0, but because you can't devide by 0, x-6 > 0, so if you ad 6 to both sides, x > 6
2007-06-12 19:34:30 · answer #2 · answered by maeamian 1 · 0⤊ 0⤋
I assume this is a fraction with denominator sqrt(x-6). domain is all reals where denominator != 0.
so solve denominator = 0.
sqrt(x-6) = 0
square both sides
x-6 = 0x = 6.
domain is all reals except 6.
2007-06-12 19:33:17 · answer #3 · answered by holdm 7 · 0⤊ 0⤋
are you saying
.............1
f(x) = --------- ...............?
..........â(x-6)
then since you can't divide by 0 or take the square root of a negative (when limited to real numbers), domain is x > 6.
2007-06-12 19:33:50 · answer #4 · answered by Philo 7 · 0⤊ 0⤋