Three years ago a city had a population of 65,000. Today it has 72,000. What is the percent of increase to the nearest whole percent?
2007-06-12 12:23:48 · 5 answers · asked by Jaycie C 1 in Science & Mathematics ➔ Mathematics
To calculate percent change, use this formula:
% change = Change in population / Initial population
= (72,000 - 65,000) / 65,000
= 7,000 / 65,000
= 11%
2007-06-12 12:28:44 · answer #1 · answered by PhysicsPat 4 · 0⤊ 1⤋
use the formula:
y = C(1+r)^t
c is the the old population(65,000)
r is the rate of change (which you are trying to find)
t is the years since the original population (3)
y is the current population (72,000)
the + is because the pop. is increasing, it it had decreased you would use a minus sign.
2007-06-12 12:32:13 · answer #2 · answered by Anya 3 · 0⤊ 0⤋
72,000-65,000=7,000
7,000 over 65,000 is what percent over 100
7,000*100=700,000
700,000 over 65,000 = 10.769 which is about 11%.
2007-06-12 12:50:15 · answer #3 · answered by Anonymous · 0⤊ 0⤋
the increase is 72,000 - 65,000 = 7,000
the percent of increase is 7,000 / 65,000 = 10.77%
2007-06-12 12:30:59 · answer #4 · answered by Philo 7 · 0⤊ 0⤋
65,000(x) = 72,000
x = 1.107
11% increase
2007-06-12 12:30:38 · answer #5 · answered by richardwptljc 6 · 0⤊ 0⤋