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2x^2 + 16x + 32

Will post the other one separate, ugh

2007-06-12 10:52:00 · 13 answers · asked by lexisayn 1 in Science & Mathematics Mathematics

13 answers

so 2 x 32 is 64

u need to find factors of 64 that add or subtract to 16, this one's easy, its 8 and 8

so


2x^2 +8x + 8x + 32 ( factor each half of the expression)

2x( x + 4) + 8(x + 4) Then you eliminate the "(x+4)" in your head to come up with the partner factor of " 2x+8"

so...

(2x + 8)(x+4)

then u still have to factor the first one,

2(x+4)(x+4)

or

2(x+4)^2


EDIT:
I triple checked this, my answer IS RIGHT, the guys below me left some steps out

2007-06-12 10:54:20 · answer #1 · answered by sellasell 3 · 1 3

You can figure out factoring by finding the multiples of the first and last number, and seeing whnich combination adds to sixteen. For example: the only two factors of 2 are 1, and 2. However, 32, has a number of multiples, such as 4 and 8; 16 and 2, etc. (It's sort of hard to explain, maybe trying looking up the scissor method for factoring.) Anyway, it factors to: (2x+8)(x+4). And the first factor can be broken down even further so the complete answer would be: 2(x+4)(x+4) or 2(x+4)^2.

2007-06-12 11:00:08 · answer #2 · answered by Sarah W 3 · 0 1

2x^2 + 16x + 32
= 2(x^2+8x+16)
= 2 (x+4)^2

2007-06-12 10:56:19 · answer #3 · answered by ironduke8159 7 · 0 1

Use AC method of factor.

Find two numbers that multiply to AC and add to B

2x^2 + 16x + 32

take out 2
2 (x^2 + 8x + 16)

find two numbers that multiply to 16 and add to 8

the two numbers are 4 and 4

since the leading coefficient is 1 after take out the 2. Plug the two numbers in factor form

2 (x + 4) (x + 4)

or

2(x+4)^2

2007-06-12 10:58:10 · answer #4 · answered by      7 · 0 1

2x^2 + 16x + 32

Your first step is to factor out the greatest common monomial; in this case, it's a constant, 2.

2(x^2 + 8x + 16)

Now factor as per usual methods.

2(x + 4)(x + 4)

or, quite simply,

2(x + 4)^2

2007-06-12 10:57:41 · answer #5 · answered by Puggy 7 · 0 1

2(x + 4)^2

2007-06-12 12:34:07 · answer #6 · answered by UNIQUE 3 · 0 0

= 2.(x² + 8x + 16)
= 2.(x + 4).(x + 4)
= 2.(x + 4)²

2007-06-12 21:49:01 · answer #7 · answered by Como 7 · 0 0

2x^2 + 16x + 32
= 2(x^2 + 8x + 16)
= 2(x + 4)^2
= 2(x+4)(x+4)

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2007-06-12 10:58:20 · answer #8 · answered by Anonymous · 0 1

first put 2 in evidence:

2(x^2 + 8x + 16)

Now you find the roots of the function into parenthesis: x=-4 or x=-4 double root

2(x+4)(x+4) = 2(x+4)^2 OK!

2007-06-12 10:59:47 · answer #9 · answered by vahucel 6 · 0 1

2(x^2+8x+16) => 2(x+4)^2

2007-06-12 10:57:12 · answer #10 · answered by Anonymous · 0 1

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