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(y-5)^2= 20?

2007-06-12 10:39:17 · 2 answers · asked by jennifer s 1 in Science & Mathematics ➔ Mathematics

2 answers

(y - 5)^2= 20

sqrt[(y - 5)^2]= sqrt[20]

y - 5 = 4.47

y = 9.47

2007-06-12 14:00:23 · answer #1 · answered by Don Danielo 2 · 0⤊ 0⤋

y² - 10y + 25 = 20
y² - 10y + 5 = 0
y = [10 ± √80] ∕ 2
y = [10 ± 4√5] ∕ 2
y = 5 ± 2√5

2007-06-13 04:55:38 · answer #2 · answered by Como 7 · 0⤊ 0⤋

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