2007-06-12 10:24:28 · 15 answers · asked by jennifer s 1 in Science & Mathematics ➔ Mathematics
5(x^2-49) = 0
(x-7)(x+7) = 0
x = 7, -7
2007-06-12 10:28:01 · answer #1 · answered by Justin L 4 · 0⤊ 0⤋
Divide everything by 5 so you get
5/5x^2-245/5=0/5
=x^2-49=0 -->x=7,-7
2007-06-12 17:38:56 · answer #2 · answered by ari b 1 · 0⤊ 0⤋
5x^2 - 245=0
5x^2=245 Add 245 to each side
x^2=49 Divide by 5 on each side
x=7 or -7 The square root of 49 is the answer.
2007-06-12 17:27:32 · answer #3 · answered by Brian M 3 · 0⤊ 0⤋
5x^2 - 245=0?
Yes!
If x = 7 or -7
2007-06-12 17:29:25 · answer #4 · answered by Apolo 6 · 0⤊ 0⤋
5x^2 = 245
x^2 = 245/5
x^2 = 49
x=7 square root
2007-06-12 17:30:37 · answer #5 · answered by ANDREA L 2 · 0⤊ 0⤋
5x^2 - 245=0
5x^2 = 245
x^2 = 245/5
x^2 = 49
x = +/- 7
2007-06-12 17:28:51 · answer #6 · answered by drea 2 · 0⤊ 0⤋
add 245 for both sides
5x^2 = 245
divide 5 for both sides
x^2 = 49
take a square root
x = -7 or 7
2007-06-12 17:31:28 · answer #7 · answered by 7 · 0⤊ 0⤋
bring the -245 over to the right hand side by adding 245.
divide the right hand side by 5 to "undo" the 5.
take the sq rt of the right hand side to "undo" the square.
remember, you're always trying to isolate the variable.
2007-06-12 17:27:25 · answer #8 · answered by Erin G 2 · 0⤊ 0⤋
5x^2 = 245
x^2 =49
x =+7 or -7
2007-06-12 17:49:57 · answer #9 · answered by Anonymous · 0⤊ 0⤋
factor out a 5
5(x^2-49)=0
divide both sides by 5
x^2-49=0 now factor
(x+7)(x-7)=0
x+7=0
x=-7
x-7=0
x=7
2007-06-12 17:28:57 · answer #10 · answered by Stop Sine 3 · 0⤊ 0⤋