find an equation of the line containing the given point and given slope
2007-06-12 07:47:47 · 4 answers · asked by bigsexywoman2004 1 in Education & Reference ➔ Homework Help
Use point slope form.
y-y1=m(x-x1)
y-0=5(x-(-4))
y=5x+4
2007-06-12 07:54:56 · answer #1 · answered by Sam 2 · 0⤊ 0⤋
Use y = mx + b, substitute the 5 for the m and the -4 for the x an d 0 for the 5 so you have 0 = 5(-4) + b so 0 = -20 + b so 20 = b Then rewrite the equation y = 5x + 20
2007-06-12 14:55:10 · answer #2 · answered by mteacher 2 · 0⤊ 0⤋
The equation of a straight line with slope m and y-intercept c is y = mx + c
For this line, you can write:
y = 5x + c ........(1)
Put x = -4 and y = 0 in (1) to find the value of c:
0 = -20 + c
Add 20 to each side:
c = 20
Put this value of c in (1) to get the equation:
y = 5x + 20.
2007-06-12 14:55:10 · answer #3 · answered by Anonymous · 0⤊ 0⤋
0 = 5(-4) + b
0 = -20 + b
20 = b
y = 5x + 20
2007-06-12 14:56:39 · answer #4 · answered by MathBioMajor 7 · 0⤊ 0⤋