solve each of the following systems by graphing 2x+3y=1 5x-2y=16?

Answer 1

first we put x=0 then we find y then we put y=0 and find x
==>first x,y = (0,1/3) ==> second x,y = (1/2,0) and then we graph it

for the next one like this again
first=(0,-8) second=(16/5,0)

Answer 2

THIS IS AN INEQUALITY PROBLEM; so, the first thing to do is to substitute....
2x+3y=1, y=-2/3x=1/3 : do you know, y=mx+b?? that's how it is set now...as for this,you can now jus punch in numbers to find y and then graph..

2). 5x-2y=16, y=5/2x+8, the 5/2 is not negatiove because the negative cancelled out when you divided both sides by the -2. this problem is the same as the first problem....because it's in the form of y=mx+b...
Goodluck!

Answer 3

Cannot draw graphs on this site.
Can give points to draw lines as follows:-
Line 1
(5,-3) and (8,-5) are suitable
Line 2
(0 ,- 8) and (4, 2) are suitable
Draw Line 1 and Line 2 to find point of intersection.

Answer 4

By graphing? I obviously can't do that here. But you can at home.

Graph one line. Then graph the other. Find out what point they intersect at. That point of intersection is your (x,y) solution to the system. It might help to first write the equations in the form of y = mx + b.

Answer 5

3y = -2x +1
y = -2/3x + 1/3
slope is -2/3, y-int is 1/3

2y = 5x -16
y = 5/2x - 8
slope is -5/2, y-int is -8