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Find the slope of any line perpendicular to the line through points (0, 5) and (-3, -4)

2007-06-12 06:53:08 · 6 answers · asked by Anonymous in Science & Mathematics Mathematics

6 answers

First: (the "m" variable represents the slope) substitute/replace the points in the slope formula which, is...
m = [second y - first y]/[second x - first x]

m = [- 4 - 5]/[- 3 - 0]
m = [- 9]/[- 3]
m = 9/3
m = 3

Sec: a line with a perpendicular slope...has the opposite slope (reciprocal)...which is, -1/3

perpendicular slope = -1/3

2007-06-12 07:29:58 · answer #1 · answered by ♪♥Annie♥♪ 6 · 3 0

To find the slope of a perpendicular line, you just need to take the negative inverse of the slope of the original line. In this problem, the slope is calculated like so:

(-4 - 5) / (-3 - 0) = -9 / -3 = 3

therefore, the slope of a perpendicular line would equal
-1/3.

2007-06-12 06:59:06 · answer #2 · answered by gavshouse32 1 · 0 0

The slope of perpendicular lines are unfavorable reciprocals of one yet another. So, if line one has a slope of +a million/2, the line perpendicular to it could have a slope of -2/a million. to locate the slope of two factors, we use the formula (y2-y1)/(x2-x1). permit's make T(4,-3) factor one and U(5,0) factor 2: 0-(-3) ------- 5-4 we've got: +3/a million. The unfavorable reciprocal of which would be -a million/3, so B is your answer :) i'm hoping I helped! Take care and happy Easter!

2016-12-12 19:09:37 · answer #3 · answered by Anonymous · 0 0

slope of given line = (-4-5)/(-3-0) = 3
so required slope of perpendicular = -1/3

2007-06-12 06:56:26 · answer #4 · answered by ironduke8159 7 · 0 0

gradient of line joining (0,5) and (-3,-4) = 5-(-4)/0-(-3) = 3

since the product of the gradients of perpendicular lines is always -1,
gradient of perpendicular line = -1/3

2007-06-12 06:57:36 · answer #5 · answered by Anonymous · 0 0

m = (- 4 - 5) / (- 3 - 0)
m = (- 9) / (-3)
m = 3
Slope of perpendicular = (-1/3)

2007-06-12 10:48:33 · answer #6 · answered by Como 7 · 0 2

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