twentyfive to the power of -2/3?

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mathematics sum, t25^-2/3

2007-06-12 06:48:12 · 4 answers · asked by shreya a 1 in Science & Mathematics ➔ Mathematics

0.116960709528515

2007-06-12 06:54:23 · answer #1 · answered by m dow 2 · 0⤊ 0⤋

25^(-2/3) = 1/(25^(2/3)) = cuberoot(25Â²) =
1/8.5498797333834849467655443627193 =
0.11696070952851464262027149440552

Doug

2007-06-12 13:54:31 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋

25^ -2/3

= 1/(25^2/3)

=1/cube root of 25^2

=1/ cube root of 625

= 1/ 5(cube root of 5)

2007-06-12 14:22:08 · answer #3 · answered by sweet n simple 5 · 0⤊ 0⤋

1/(5 * 5^(1/3)) looks neater, but the other answers are also correct.

2007-06-12 14:14:51 · answer #4 · answered by Mathsorcerer 7 · 0⤊ 0⤋