An airplane covered 15 mi of its route while decreasing
its altitude by 24,000 ft. Find the slope of the line of descent that was followed.
(1mi=5280) Round to the nearest hundredth.
2007-06-12 06:40:20 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
triangle
think height = 24,000 ft
long leg = 15mi but convert to ft using 5280 ft in 1 mile
slope = rise over run so height over long leg
2007-06-12 06:44:09 · answer #1 · answered by Winnebago 1 · 0⤊ 0⤋
Think rise over run...
Rise/run ==> Rise is -24,000ft Run is 15 miles
First you must convert the feet into miles
1/5280=x/24000
x=4.54545454... this number will be Neg. since it is descending
now you have ur slope -> -4.5454545454.../15= -0.3030303...
Your answer is -0.30
2007-06-12 13:52:58 · answer #2 · answered by Jonathan C 1 · 0⤊ 0⤋
Convert the altitude into miles, then slope = change in altitude / change in linear direction. The plane is descending, so your answer will be negative.
2007-06-12 13:45:05 · answer #3 · answered by Mathsorcerer 7 · 0⤊ 0⤋
change in y = 24000 ft
change in x = 15*5280 = 79200 ft
gradient = y/x = 24000/79200 = 0.30
2007-06-12 13:45:55 · answer #4 · answered by Daniel A 2 · 0⤊ 1⤋
Slope = negative24000ft/[15mi(5280ft/mi)].
2007-06-12 13:53:26 · answer #5 · answered by Mark 6 · 0⤊ 0⤋
tan x = 24000/79200
x = 16.86 degs
Slope = -24000/79200 = -0.30
2007-06-12 13:48:00 · answer #6 · answered by gebobs 6 · 0⤊ 0⤋