Help me Solve please!!!!!?

Question

lim [2x2/x-3 + 6x/3-x]
x>3

Written: limit x approaching 3. [ 2x squared/ x-3 + 6x/3-x]

Answer 1

Hi,

lim [2x2/x-3 + 6x/3-x] = 6
x>3

lim [2x²/x - 3 + 6x/3-x] =
x>3

Multiply 2nd fraction by -1/-1

lim [2x²/x - 3 - 6x/x-3] =
x>3

Combine into one fraction.

lim [(2x² - 6x)/(x-3)] =
x>3

Factor out the GCF.

lim [(2x(x - 3)/(x-3)] =
x>3

Cancel the x - 3 factors.

lim (2x) = 2(3) = 6
x>3


I hope that helps!! :-)

Answer 2

Here we go. I'll write "Squared" as ^2 and the fractions will have (numerator)/(denominator)

Let's look at the expression:
(2x^2)/(x-3) + (6x)/(3-x)
=(2x^2)/(x-3) - (6x)/(x-3) ( multiply the last fraction by (-1)/(-1) )
=(2x^2-6x)/(x-3) (add the fractions with common denominators)

Now, if we plug in 3, we get 0 on the bottom of that fraction, which is bad, so we'll factor the numerator.
= (2x * (x - 3) )/(x - 3)
= 2x (cancel out the x - 3)

Now we just plug 3 into that expression and get
2x = 2 * 3 = 6.

So the limit as x approaches 3 is 6.

Answer 3

2x^2/(x-3) + 6x/(3-x) = ((2x^2 - 6x)/(x-3)) = (2x)(x-3)/(x-3) = 2x.

Lim x-->3 2x = 6.

Answer 4

=Limit(2x^2/x-3 + 6x/3-x)
.x-->3
=Limit(6x^2-2x^3+6x^2-18x)/(x-3)*(3-x)
.x-->3
=Limit(2x(x^2-6^x+9)/(x-3)^2)
.x-->3
=Limit(2x(x-3)^2/(x-3)^2)
.x-->3
=Limit(2x)
.x-->3
=2*3=6

Answer 5

= -2x(x^2 - 8x + 9)/((x-3)(3-x)

I'm lost...sorry

Answer 6

The question was not clear.
Just make it clear with X and *. confusing...