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Your company is considering various locations for expansion. It is your job to check out the various areas and the friendliness for business. One of the factors of interest is the average temperature.
As you start your drive, the first electronic sign you see states that the temperature is 22.0 °C.
You are not very familiar with this temperature scale. As you drive 10 miles east, the temperature is now listed as 69.8 °F.
The next temperature, out another 10 miles, is 20.0 °C. It seems that temperature is declining with distance traveled to the east.
However, you cannot tell, unless you are able to convert from one temperature scale to another.

Converting from C to F
To do so, you will need to solve a linear equation.
The linear equation that relates °C to °F is as follows:
°F = 1.8 °C + 32.0
Provide a plot of temperature versus distance east.
HINT: Let temperature be the “x” and distance be the “y”. Use the table given to provide the (x,y) pairs for you to plot.

2007-06-12 05:47:39 · 13 answers · asked by Anonymous in Science & Mathematics Mathematics

my question is, what does my equation look like if I use the temperature for x and the distance for y? Do I just make up values for these? What formula do I use? PLEASE HELP!

2007-06-12 05:48:41 · update #1

13 answers

Well. I can solve any Math Problems.
But it's very long question. I don't want to waste time for reading this question.
Sorry.!!

2007-06-12 06:23:32 · answer #1 · answered by K.Y 2 · 0 2

First of all I would recommend switching what your x and y axis represent. I would do distance as x and temperature as y. Since traveling east is somewhat related to the temperature drop makes sense opposed to saying that since temperature is dropping you must be traveling east. I won't do the work for you but I will say what you should do is subtract the first temp reading from the last and divide that by the total distance traveled and call that number k.

Then you have an equation :
y(temp) = k * x(distance) + b

If you don't know what the b is or how to derive it then you don't need to be asking this question anyway.

2007-06-12 06:05:28 · answer #2 · answered by itstwoam 2 · 0 0

y = -x/10+22

y=0 >> 0+22 = 22 degrees C
y= 10 >> -1+22 = 21 degrees C (69,8 F)
y=20 >> -2+22 = 20 degrees C
edit:
disregards the above
ooops sorry - the linear equation should be
x=-y/10+22 (for Celsius)


y=0 >> 0+22 = 22 degrees C (starting temp)
y= 10 >> -1+22 = 21 degrees C (69,8 F) (temp at 10 miles)
y=20 >> -2+22 = 20 degrees C (temp at 20 miles)

For the temperature conversion:
F=1.8C+32
F=22*1.8+32 = 71,6
(69,8 F -32)/1.8 = 21 C
F=20*1.8 + 32 = 68
so temperature declines 1° celsius or 1.8 defrees F for every 10 miles you drive
I hope I remember my maths well enough

2007-06-12 06:10:11 · answer #3 · answered by Martin S 7 · 0 0

Summary of variables and values:

Temperature at point A (origin): 22.0 °C
Temperature at point B: 21 °C (69.8 °F)
Temperature at point C: 20 °C

Given a non-exponential, i.e. linear increase in x (temperature), the equation is:

-1 °C/10 miles or -0.1 °C/mile traveled due east or
-1.8 °F/10 miles or -0.18 °F/mile traveled due east

Equation in practice (example):

Temperature (°C) at point Z, 56 miles due east of point A:

Step 1: 56/10 = 5.6
Step 2: 5.6 * -1 °C = -5.6°C

If temp. at point A = 30 °C, then temp. at point Z = 24.4 °C.

No tables or plotting required. It's simple math. Hope this helps.

P.S. In practice, such temperature mapping would be extremely difficult and highly inaccurate, as Mother Nature can't be explained in mathematical terms, at least not with those currently at our disposal.

2007-06-12 06:18:50 · answer #4 · answered by Chris 3 · 0 0

Well it doesn't take a math genius to figure it out.
Using the formula C = (F-32)/1.8 the mystery temperature is easily solved to be 21 C. This means the temperature is dropping 1 degree C every 10 miles you go East.

I think the graph will be easier to read if you let the distance be X and the temperature be Y.

Temp
.... |
22 |+
.... |
21 |.......... +
.... |
20 |..........................+
.... |
.... |__________________
0............10............20
......... Miles East of start

2007-06-12 06:00:00 · answer #5 · answered by Steven 4 · 0 0

The problem with this problem is that you first have to make a choice: is the temperature on a sign in degrees F or degrees C. Depending upon your answer you may or may not have to convert scales.

However, let's presume that you will convert from F to C before plotting your points. (F = 32)/1.8 = C, so 69.8F = 21 C. Now you have your points: (0,22), (10,21), (20,20), so your plot line will be:

C = -0.1m + 22 where m = distance in miles

2007-06-12 06:00:48 · answer #6 · answered by Mathsorcerer 7 · 0 0

X=temp.
Y=distance.
So, when Y=0, x=22degreesC.
when y=20, x=20degreesC.

When y=10, x=69.8degreesF, so you have to convert to degreesC. They give you the formula to do so.
Now, you have 3 points to plot on graph paper.
(x,y) pairs are:
(22,0)
(20,20)
(21,10)
the graph has a downward slope, the temperature IS decreasing with increased distance East.

2007-06-12 05:59:35 · answer #7 · answered by mikecraig11 4 · 0 0

I often might assist you to, yet in view which you're soliciting for each and each answer to thirty problems, that in basic terms tells me you published all the homework for somebody else to do for you. by utilizing the time you complete typing those up, you may've been performed with it. end being so lazy. those problems are so uncomplicated it is not even humorous. guess that makes all of us a genius.

2016-10-09 01:31:42 · answer #8 · answered by ehler 4 · 0 0

Just draw three columns. One for distance, one for temp (C) and one for temp (F). Fill in all three values, and you;ll find that there is a linear relationship between distance and temperature. Every 10 miles the temp drops by 1.8 F or 1 C.

Your table should look like this
distance ---- -----temp(C)-------- -------temp(F)
0---------- ----------22----------- ------------71.6
10-------- ----------21----------- ------------69.8
20-------- ----------20--------- --------------68

2007-06-12 05:57:22 · answer #9 · answered by Dr D 7 · 0 1

Was this on the GCSE paper last year - cause I got one jst like this - missed it out but having a go now lol if i get it I'll post it to you - but I wouldnt count on it!

2007-06-12 05:57:07 · answer #10 · answered by Anonymous · 0 3

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