How much 3.5% milk and 1.0% milk must be mixed to produce 220 gallons of 2.0% milk?
2007-06-12 05:18:31 · 4 answers · asked by Kuroi 3 in Science & Mathematics ➔ Mathematics
0.035 x + 0.01 Y = 0.02(x+y)
x+y = 220
y = 220-x
0.035x + 0.01(220-x) = 0.02(x + 220 - x)
0.035x + 2.2 - 0.01x = 4.4
0.034x = 2.2
x = 2.2 / 0.034 = 64.7 (gallons of 3.5%)
y = 155.3 (gallons of 1%)
2007-06-12 05:26:21 · answer #1 · answered by Grant d 4 · 1⤊ 0⤋
Let x = the number of gallons of 3.5% milk
and y= the number of gallons of 1.0% milk
x + y = 220
.035x + .01y = .02(220)
Solving the equations gives x=88 and y=132
2007-06-12 12:32:50 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Let there be x amount of first mixture and y amount of second mixture
Then we have
........Milk...Water
First...3.5x + 96.5x
Second..1.0y + 99.0y
Now as the resultant mixture is 2%
so (3.5x + 1.0y)/100(x+y) * 100 = 2
or 3.5x + 1.0 y = 2x + 2y
or 1.5x = 1y ....(1)
similarly from question
x + y = 220 gallons
or x + 1.5x = 220 gallons ... from (1)
or 2.5x = 220 gallons
or x = 88 gallons
or y = 220 - 88 = 132 gallons
2007-06-12 12:31:23 · answer #3 · answered by Pareshan Atma 2 · 0⤊ 0⤋
he he he he rofl
2007-06-12 12:20:36 · answer #4 · answered by gjmb1960 7 · 1⤊ 1⤋