You need to find a linear equation that fits the two points you have :(4, 0) and (6,6).
Use the slope-intercept form: y = mx + b.
Slope (m) is defined as the change in y over the change in x. Let (x1, y1) = (4,0) and (x2, y2) = (6,6). Then, m = (y2 - y1)/(x2 - x1)
m = (6 - 0)/(6 - 4) = 6/2 = 3
Now, use one of the points to find the intercept, b, using the m we just found. Let's use (x1, y1)
y1 = m(x1) + b
0 = 4(3) + b
0 = 12 + b
b = -12
Now, you've got the right equation. Just plug m and b into the generic formula:
y = 3x - 12
E is correct.
2007-06-12 04:41:52
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answer #1
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answered by Sci Fi Insomniac 6
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When you have a function f(4) = 0, this means that same as saying f(x) = 0, when x = 4. The same for f(6) = 6, is the same as f(x) = 6, when x = 6. The number in the brackets is what x equals.
So, plug in 4 for x in the possible equations and see if the answer comes out to be 0. For every equation that it does work, plug in 6 for x and see if the answer turns out to be 6. The one equation that works for both possible values of x is the right equation.
A. 2/3x - 4 = 2(4)/3 -4 = 8/3 - 4
This does NOT equal 0
B. x + 2 = 4 + 2 = 6
This does NOT equal 0
C. x - 4 = 4 - 4 = 0
This does equal 0. So check with 6:
C. x - 4 = 6 - 4 = 2
This does NOT equal 6
D. 3/2x + 6 = 3(4)/2 + 6 = 12/2 + 6 = 6 + 6 = 12
This does NOT equal 0
E. 3x - 12 = 3(4) - 12 = 12 - 12 = 0
Now check with 6:
E. 3x - 12 = 3(6) - 12 = 18 - 12 = 6
E. 3x - 12 checks out. This is the correct answer.
2007-06-12 11:48:33
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answer #2
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answered by DanG. 2
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E. 3x-12
Because f(4) = 3(4) -12 = 0 and f(6) = 3(6)-12 = 6.
y = f(x) means y is a function of x. The value of y depends on x. So x is called the independent variable and y is the dependent variable.
If y=f(x) =x, then f(1) =1, f(2) =2, f(3) =3 , etc.
If f(x) = x^2+2x+1, then f(1)= 1^2 +2(1) +1 = 4.
The values that x can take on is called the Domain. The values that F(x) takes on is the range of the function.
Functions are characterized by having only one value of y for each value of x. If the same value of x generates two values of y that arethe same, then what you are dealing with is not a function. If you are looking at a graph, run a vertical line from left to right across the graph. If the vertical line cuts the graph in more than on place, then the graph is not a function. For example, if you are looking at the graph of a circle, when you move the vertical line from left to right , you would find that the vertical line would cutt the circle in two places. Hence a circlr is not a function.
2007-06-12 12:01:42
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answer #3
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answered by ironduke8159 7
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PLug in the given values (4 and 6) to determine if they come out to the right results (0 and 6):
(A) (2/3)(4) - 4 = -4-3 => does not equal 0
(B) 4 + 2 = 6 => does not equal 0
(C) 4 - 4 = 0 => ok so far
6 - 4 = 2 => does not equal 6
(D) (3/2)(4) + 6 = 12 => does not equal 0
(E) 3(4) - 12 = 0 => ok so far
3(6) - 12 = 6 => ok
(E) is correct.
2007-06-12 11:40:22
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answer #4
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answered by yeeeehaw 5
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There's a few ways you could solve this (like with most things in math). What I would do is just plug in the numbers and see if they work.
if:
f(x)=3*x-12 then:
f(4)=3*4-12
Do you see how that works?
Does that equal 0?
How about f(6)? Does 3*6-12 equal 6?
This is good stuff to know, even though it doesn't seem so right now, it trains you in thinking logically, problem solving, creativity...yeah that's right, creativity.
2007-06-12 12:00:25
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answer #5
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answered by ivan k 5
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that means that when x =4, f(x) = 0 and
when x = 6 f(x) = 6.
Plug it in.
3 * (6) - 12 = 6. thus, f(6) = 6.
3 * (4) -12 = 0 thus f(4) = 0.
2007-06-12 11:41:57
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answer #6
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answered by khaoticwarchild 3
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The answer is E.
The way you solve this is as follows:
3(4) - 12 = 0
3(6) - 12 = 6
2007-06-12 11:42:22
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answer #7
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answered by wbv8799 1
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D
2007-06-12 11:40:11
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answer #8
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answered by orange 1
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3⤋