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Graph the solution set to the compound inequality.
1#
x>3 or x<-3
2#
x > -2 and x < or equal to 4

2007-06-12 03:41:46 · 3 answers · asked by christopher l 1 in Science & Mathematics Mathematics

3 answers

How do you expect us to graph this?

The first is a pair of dashed (to indicate "not equal to") vertical lines at x=-3 and x=+3 and the areas to the left and right shaded.

Do the same for the second, but use a solid line at +4. The area shaded is between the lines.

2007-06-12 03:47:46 · answer #1 · answered by gebobs 6 · 0 0

---------------- (8)? --------------- ?(13) The graph of x > 8 is a quantity line with 8 marked and an open circle drawn around 8 to teach that 8 itself isn't part of the answer then an arrow pointing to the suited The graph of x < 13 is a quantity line with 13 marked and an open circle drawn around 13 to teach that 13 itself isn't part of the answer then an arrow pointing to the left be careful with the way they be conscious it: in the event that they needed x > 8 and x < 13 then: The simultaneous answer for the two x > 8 AND x < 13 is the part of the quantity line that represents the two the inequalities on a similar time ... so for 8 < x < 13 ... so the part of the line between the rotated 8 and the rotated 13 (8)___________________(13) and in era notation the answer set is (8, 13) yet ... they do no longer prefer that they like x > 8 OR x < 13 ... so as that includes each and every conceivable quantity ... no longer something is excluded b/c numbers > 8 contain each and every thing extra effective than 8 ... including 13 and numbers < 13 contain each and every thing decrease than 13 including 8 ... so the answer set is -? < x < +? and in era concept the answer set for x > 8 OR x < 13 is (-?, +?)

2016-10-17 00:35:46 · answer #2 · answered by ? 4 · 0 0

dude, answer your own homework questions.

2007-06-12 03:46:45 · answer #3 · answered by Al_Hattal 2 · 0 0

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