2007-06-12 03:31:19 · 13 answers · asked by Heather 1 in Science & Mathematics ➔ Mathematics
slope (m) and y-intercept (b) are found in the equation y = mx + b. If given the standard equation of the line (Ax+By=C), convert to slope-intercept form to find the slope and y-intercept.
2x-5y=20
-5y= -2x+20
y = (2/5)x -4
m = 2/5
b = -4
The slope and y-intercept could also be found from the standard equation.
m = -A/B = -(2/-5) = 2/5
b = C/B = 20/-5 = -4
HTH
2007-06-12 03:39:29 · answer #1 · answered by whatcanmaxdo4u?everythingupscant 3 · 1⤊ 0⤋
That can be written as -5y = -2x + 20 or
5y = 2x - 20
and y = 2/5 x - 4
which is of the standard form y = mx + c
So, slope m = 2/5 and intercept c = -4
2007-06-12 03:36:38 · answer #2 · answered by Swamy 7 · 1⤊ 0⤋
To find the slope you need to put it in slope-intercept form.
Recall that the slope-intercept form is
y = mx + b, where m is the slope and b is the y-intercept
2x - 5y = 20
Subtract 2x from each side
-5y = -2x + 20
Divide both sides by -5
y = -2x/-5 + 20/-5
Simplify
y = (2/5)x - 4
m = slope = 2/5
b = y-intercept = -4
2007-06-12 03:34:00 · answer #3 · answered by MsMath 7 · 0⤊ 0⤋
First you have to solve for y.
You subtract 2x and get -5y=-2x+20
Then you divide by -5 and get y=(2/5)x+20
This is slope-intercept form or y=mx+b
The m=slope and b=y-intercept
so slope=(2/5) and the y-intercept=20
2007-06-12 03:38:29 · answer #4 · answered by scars of friends 1 · 0⤊ 0⤋
y = mx + c
where m = slope and c is the y-intercept
So, write the equation to look like the equation above
2x - 5y = 20
5y = 2x - 20
y = (2/5)x - (20/5)
y = (2/5)x - 4
Therefore the slope is 2/5 and y-intercept is -4
2007-06-12 03:37:21 · answer #5 · answered by topsyk 3 · 0⤊ 0⤋
This Site Might Help You.
RE:
Find the slope and y-intercept of the graph of 2x - 5y= 20?
2015-08-08 10:19:19 · answer #6 · answered by Anonymous · 0⤊ 0⤋
Solve for y.
Subtract 2x to both sides.
-5y = -2x + 20
Divide - 5 to both sides.
y= 2/5 x - 4
Slope is 2/5
Y-intercept is -4
2007-06-12 04:23:34 · answer #7 · answered by Hector 1 · 0⤊ 0⤋
5y = 2x - 20
y = (2/5).x - 4
slope = 2/5
Cuts y axis at y = - 4
2007-06-12 03:36:32 · answer #8 · answered by Como 7 · 0⤊ 0⤋
juat put it into slope intercept form, y=mx+b
subract 2x from both sides
-5y=-2x+20
divide by -5
y=2/5x-4
slope=2/5
y-intercept= -4
2007-06-12 03:35:38 · answer #9 · answered by Anonymous · 0⤊ 0⤋
2x - 5y = 20
2x - 5y - 2x = - 2x + 20
- 5y = - 2x + 20
- 5y / - 5 = - 2 / - 5 + (20 / - 5)
y = 2/5 + ( - 4)
y = 2/5 - 4
- - - - - - - -
Slope 2/5
y intercept - 4
- - - - - - - - - s-
2007-06-12 03:47:38 · answer #10 · answered by SAMUEL D 7 · 0⤊ 0⤋