Given R(-1, 3) and S(2, 4), find the magnitude of vector RS.?

Answer 1

RS=sqrt(9+1)=sqrt(10)=3.16 answer

Answer 2

Vector RS = Vector S - Vector R

Vector S = OS (where O is the origin)
Vector R = OR

Vector OS = Vector OR + Vector RS
=> Vector RS = Vector OS - Vector OR
=> Vector RS = (-1-2), (3-4) = (-3, -1)

Therefore |Vector RS| = sqrt((-3)^2 + (-1)^2)
= sqrt(10) = 3.162277

Answer 3

RS
= OS - OR
= (2 , 4) - (-1 , 3)
= (3 , 1)

Magnitude of RS
= |RS|
= √(3² + 1²)
= √10 units

Answer 4

Think of this as a right angle triangle with the hypothenuse defined by the two points R(-1, 3) and S(2, 4).

The length of the other two sides is 2 -- 1 = 3 and 4 - 3 = 1

Using pythagours square of hyp = sum of the square of the other two sides.

hyp^2 = 3^2 + 1^2
= 9 + 1
= 10
therefore hyp = root 10 and since distance is positive you do not use - root 10

root 10 ~~ 3.16

HTH
PeterVincent

Answer 5

vector RS = (3 1)
|RS| = √(3² + 1²)
|RS| = √10

Answer 6

The formula is sqrt((x2-x1)^2+(y2-y1)^2)
>> sqrt((2--1)^2+(4-3)^2)
>> sqrt(3^2+1^2)
>> sqrt(9+1)
>> sqrt(10)
>> 3.16 units