x² - 3x = 4x - 1
x² - 3x - 4x = 4x - 1 - 4x
x² - 7x = - 1
x² - 7x + 1 = -1 + 1
x² - 7x + 1 = 0
Quadratic Formula
x = - b ± √b² - 4ac / 2a
x² - 7x + 1 = 0
a = 1
b = - 7
c = 1
x = - (- 7) ± √(- 7)² - 4(1)(1) / 2(1)
x = 7 ± √ 49 - 4 / 2
x = 7 ± √45 / 2
x = 7 ± 6.708203933 / 2
- - - - - - - - -
Solving for +
x = 7 + 6.708203933 / 2
x = 13.70821093 / 2
X = 6.854101966
- - - - - - - - - -
Solving for -
X = 7 - 6.708202933 / 2
x = 0.291796068 / 2
x = 0.145898034
- - - - - - - - -s-
2007-06-11 23:29:45
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answer #1
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answered by SAMUEL D 7
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This question can be solved by bringing all your terms to the left hand side of the equation. This becomes:
x² - 7x + 1 = 0
Since the equation cannot be factorised, we must solve it using the general formula:
x = [-b ± √ (b² - 4ac) ] / 2a
The coefficient of x² is a, that of x is b, and c is -1.
Substituting these values into the equation:
x = [- (-7) ± √ { (-7)² - 4(1)(1) } ] / 2(1)
Simplifying this:
x = (7 ± √45) / 2
x = 0.146 (3sf) OR x = 6.85 (3sf)
There are 2 answers since this is a quadratic equation.
2007-06-11 22:53:35
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answer #2
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answered by Anonymous
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x^2 -3x = 4x -one million x^2 - 7x + one million = 0 (subtracting 4x and including one million to the two section) From right here, you could the two use the quadratic formulation simply by fact the equation isn't unquestionably factorable. x1 = [7 + sqrt(40 5)]/2 x2 = [7 - sqrt(40 5)]/2
2016-10-07 08:34:34
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answer #3
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answered by ? 4
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Put it in 'standard' quadratic form
ax² + bx + c =0 by subtracting 4x - 1 from, noth sides to get
x² - 7x +1 = 0 Now solve it using the quadratic formula.
Doug
2007-06-11 22:37:23
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answer #4
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answered by doug_donaghue 7
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You can use simple algebra to solve this:
Move the 4x to the other side to form x^2 - 3x - 4x = -1
Now move the -1 to form x^2 - 3x - 4x + 1 = 0
Collect like terms to form x^2 - 7x + 1 = 0
Now you can solve it!
2007-06-11 22:35:23
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answer #5
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answered by รզlεսռց ☆ 6
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x^2 - 3x = 4x -1 <==> x^2 - 7x + 1 = 0, and a = 1, b = -7, c = 1 , so:
x_1,2 = [ -(-7) (+/-) sqrt((-7)^2 - 4*1*1) ]/2*1 = [ 7 (+/-) sqrt(45)]/2
So the solutions are [ 7 - sqrt(45)]/2 and [ 7 + sqrt(45)]/2
Regards
Tonio
2007-06-11 22:39:29
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answer #6
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answered by Bertrando 4
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This is by far the easiest equation i've ever seen, the answer is X^2-7X+1=0. that's bout it i think. laters.
2007-06-11 22:37:14
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answer #7
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answered by Anonymous
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x^2-7x+1=0
for ax^2+bx+c=0
x=[-b+-sqrt(b^2-4ac)]/2a
here a=1, b=-7, c=1
x=[7+-sqrt(49-4)]/2
x=[7+-3sqrt(5)]/2
x=(7+3sqrt 5)/2 & (7-3sqrt(5)/2
2007-06-11 22:38:57
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answer #8
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answered by Jain 4
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x² - 7x + 1 = 0
x = [ 7 ± √45] / 2
x = 6.85 , x = 0.145
2007-06-12 04:47:05
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answer #9
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answered by Como 7
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x^2-3x=4x-1
x^2-7x+1=0
x=1/2[7+/-sqrt(49-4)]
=1/2[7+/-sqrt(45)] answer
2007-06-12 00:22:28
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answer #10
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answered by Anonymous
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