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I'm trying to build a wind tunnel to do some testing in, and I'm having trouble figuring how to determine this so I know the proper fan to purchase for this. I don't have an anemometer yet, but that will only really be needed during testing to monitor the speeds. I just need to figure out how big of a fan (CFM requirements) I'm gonna need to achieve these high wind speeds in the tunnel without having to go through a dozen fans using trial and error. Any help with this would be greatly appreciated. Thanks!

2007-06-11 21:08:30 · 3 answers · asked by dragon_slayer79 2 in Science & Mathematics Mathematics

3 answers

Calcualte the area of cross-section of the inside of the pipe in square feet. Think of a cylinder of length l, which is 80 / 60 = 4/3 = 1.333 miles long. Convert that length into feet. If you multiply the area in square feet with the length in feet, you get the volume per minute requirement which is CFM (Cubic Feet per Minute). You will need some extra to take care of losses, friction with the surface of the pipe etc.

I am not doing the maths because I know you can do it.

2007-06-11 21:26:40 · answer #1 · answered by Swamy 7 · 0 0

The winds of substitute are blowing extraordinarily sturdy in the present day. A transferring company is drawing close Monday to do an evaluation. we are transferring on the top of this month from AL to AZ. I easily have by no ability lived everywhere inspite of the indisputable fact that the South, and that i'm extremely apprehensive about transferring so a methods away.

2016-11-23 13:15:01 · answer #2 · answered by friedman 4 · 0 0

The flow of a fluid through a conduit is the product of the cross-sectional area and the velocity of the fluid (Q = AV).

The area of a pipe with a nominal diameter of 6" is

A = pi*[(6/12)^2]/4 = 0.196 ft^2

Convert velocity to ft/min

V = 80*5280/60 = 7040 ft/min

Q = AV = 0.196*7040 = 1382 cfm

2007-06-14 10:07:01 · answer #3 · answered by sweetwater 7 · 0 0

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