In quadratic equation, what does y=mx+c mean? Thanks.?

Question

For m, x and c. Thanks.

Answer 1

y = mx + c

In this form, the constant m will determine the slope or gradient of the line; and the constant c will determine the point at which the line crosses the y-axis.

x is the point on the x-axis.

Answer 2

It has nothing to do with quadratic equations.

y = mx + c is the linear equation representing a line on the Cartesian Plane with slope m and y-intercept of c. y - intercept means the coordinate where the line meets y - axis. It is always of the form (0, c)

In quadratic equations, when you have to draw the graph of a quadratic polynomial in x, you let the quadratic equation equal y instead of 0

y = ax^2 + bx + c

You put a value of x and get a value of y. Getting a set of coordinates for the points, you mark them and join them with a freehand curve. There are some point(s) where the curve meets/touches x - axis. Those point(s) are the zeroes of the polynomial. Those zeroes, of course, are roots of the quadratic equation. Sometimes, the curve never touches x - axis. Then ax^2 + bx + c = 0 has no real roots

Answer 3

That equation is that of a straight line and not a quadratic equation.

y = mx + c represents a straight line with a slope of 'm' and an intercept on y-axis of c. It represents a linear relationship between an independent variable x and a dependent variable y.

ax^2 + bx + c = 0 is the standard form of a quadratic equation. x^2 + 2x + 1 = 0 is a quadratic equation with roots of x = - 1

Answer 4

y = mx + c is the general formula of a 'STRAIGHT' line
'm' refers to the GRADIENT of the line (or the slope of the line) and can be positive (looks like --> / ) or negative (looks like --> \ )
c- is the y-intercept and refers to where the graph cuts the y-axis (ie at what value the graph cuts through the yaxis)

So if you are given the gradient or y-intercept you can just substitute these values into this general equation y = mx+c to give you the equation of the straight line.

If you have 2 points (x1,y1) and (x2,y2) you can use these two points to find the gradient of the line by using the formula:
m = ( y2 - y1 ) / (x2 - x1)

If you are given the gradient and 1 point (x1,y1) you can substitute it into the equation:
y - y1 = m(x - x1) and this will give you the equation of the line.

The general formula of a quadratic is ax^2 + bx + c
A positive quadratic (ie a is positive) looks like a smiley face )
and
A negative quadratic (ie. a is negative) looks like a frown or sad face (

Hope this helps =]

Answer 5

That is the equation of a straight line a quadratic equation would take the form: ax^2 + bx + c = 0

Answer 6

The formula you wrote is for linear equation.
In this form, the constant m will determine the slope or gradient of the line; and the constant b will determine the point at which the line crosses the y-axis. x is the point on the x-axis.

Quadractic eqation
ax^2+bx+c=0
The letters a, b, and c are called coefficients: the quadratic coefficient a is the coefficient of x2, the linear coefficient b is the coefficient of x, and c is the constant coefficient, also called the free term.

Answer 7

m = (y-c)/x

x = (y-c)/m

c = y - mx

but this is not a quadratic equation, since there is no term that is squared ( to the second degree)
this is an example: ax^2 + bx = c

Answer 8

there isn't any equivalent to the meanings for the immediately line. contained in the quadratic they are basically the coefficients of the powers of x. They do impact the shape of the curve. i assume 'c' is the equivalent of intercept, as even as x=0 then y=c

Answer 9

its a linear equation .equation of a straight line.m represents the slope of the line .