Chemistry Question?

Question

4NaCL + 2SO2 +2H2O + O2 --> 2Na2SO4 + 4HCL

10 moles of each reactant, which will determine how much Na2SO4 is produced

100 moles " " Na2SO4 is produced

How do you determine this, Im assuming its looking for a limiter but I dont understand what to do next

Answer 1

If there are 10 moles of each reactant, NaCl is the limiter, and you will get 5 moles of Na2SO4.

So to get 100 moles of Na2SO4, you need 200 moles of NaCl, 100 moles of SO2 and so on.

Answer 2

Yes, in this question you have to determine which reagent is the limiting reagent. By looking at the equation, and given that there is 10 mol of each reagent, we can deduce that NaCl is the limiting reagent, because 2 mol of SO2 reacts with 4 mol of NaCl to form 2 mol of Na2SO4. Hence, 10 mol of SO2 must react with 20 mol of NaCl . However, since there is only 10 mol of NaCl available, the NaCl is the limiting reagent.

With this, we can conclude that all 10 mol of NaCl will react with 5 mol of S02 to form 5 mol of Na2SO4.