2007-06-11 18:59:12 · 13 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
7(3x + 4) = 8(2x + 5)+13
21x+28=16x+40+13
21x-16x=40+13-28
5x=25
x=25/5
x=5
2007-06-11 19:03:22 · answer #1 · answered by Jain 4 · 0⤊ 0⤋
Okay first you start out by distributing right? By bring the 7 into the (3x + 4) you'll get a 21x+28, and by bringing the 8 into the (2x+5) you'll get a 16x +40...
So you're equation looks lilke
21x+28= 16x+40+13. Definitely combine the 40 and 13, which will leave you with 53.
21x+28=16x+53. Now simplify. Bring the like terms together. Take 16x, and subtract it out of the left side, bringing it to the right. That will leave you with:
5x+28=53 Now all you have to do is subtract 28 from the right side, bring it to the left. That will leave you with
5x=25. Now all you have to do is isolate (leave by itself) the x, and your fine. Divide the 5 over and you will get your answer....
x=5
2007-06-12 02:09:23 · answer #2 · answered by Anonymous · 0⤊ 0⤋
7 (3x + 4) = 8 (2x + 5) + 13
7 (3x + 4) = (8 (2x) + 8(5)) + 13
7 (3x + 4) = (8 (2x) + 40) + 13
7 (3x + 4) = 16x + 40 + 13
7 (3x + 4) = 16x + 53
7 (3x) + 7 (4) = 16x + 53
7 (3x) + 28 = 16x + 53
21x + 28 = 16x + 53
(21x + 28) - (16x + 53) = 0
(21x + 28) - 16x - 53 = 0
21x - 16x + 28 - 53 = 0
21x - 16x - 25 = 0
5x - 25 = 0
5x = 25
5x/5 = 25/5
x = 5^2/5
x = 5^(2-1)
x = 5
THIS IS THE VERY LONG PROCESS.. ;)
2007-06-12 04:50:51 · answer #3 · answered by Rey Arson II 3 · 0⤊ 0⤋
7(3x + 4) = 8(2x + 5)+13
21x + 28 = 16x + 40 + 13
21x + 28 = 16x + 53
21x = 16x + 53 - 28
21x = 16x + 25
21x - 16x = 25
5x = 25
x = 25/5
x = 5
2007-06-12 03:54:45 · answer #4 · answered by ishita s 2 · 0⤊ 0⤋
7(3x + 4) = 8(2x + 5)+13
21x + 28 = 16x + 40 + 13
21x + 28 = 16x + 53
21x + 28 - 28 = 16x + 53 - 28
21x = 16x + 25
21x - 16x = 16x + 25 - 16x
5x = 25
5x/5 = 25/5
x = 5
2007-06-12 02:05:53 · answer #5 · answered by rooster1981 4 · 0⤊ 0⤋
7(3x+4)=8(2x+5)+13
=>21x+28=16x+10+13
=>21x+28=16x+23
=>5x=5(divide by 5)
=>x=1
2007-06-12 10:11:47 · answer #6 · answered by honey 1 · 0⤊ 0⤋
7(3x + 4) = 8(2x + 5)+13
21x+28=16x+40+13
21x-16x=53-28
5x=25
x=5#
2007-06-12 02:56:27 · answer #7 · answered by jackleynpoll 3 · 0⤊ 0⤋
7(3x+4)=8(2x+5)+13
21x + 28=16x+40+13
21x-16x=40+13-28
5x=25
x=5
2007-06-12 02:17:47 · answer #8 · answered by puzzlesw 2 · 0⤊ 0⤋
7(3x + 4) = 8(2x + 5) + 13
Multiply out:
21x + 28 = 16x + 53
Combine like terms:
5x = 25
Divide:
x = 5
Hope this helps!
2007-06-12 02:04:38 · answer #9 · answered by p37ry 5 · 0⤊ 0⤋
7(3x + 4) = 8(2x + 5)+13
or 21x+28=16x+40+13
or 5x=53-28=25
or x=5
2007-06-12 02:05:37 · answer #10 · answered by Sumita T 3 · 0⤊ 0⤋