solve for x. 2cot^2x-1=0?

Answer 1

2cot^2x-1=0
cot^2x = 1/2
1/ tan^2x = 1/2
tan^2x = 2
tan x = ±√2
either tan x = √2, x = 54.7
or tan x = -√2, x = 305.3

Answer 2

2 cot² x - 1 = 0
cot² x = 1/2
tan² x = 2
tan x = ±√2
if tan x = √2, x = 0.9553 + πn
if tan x = -√2, x = -0.9553 + πn

Answer 3

cot ² x = 1/2
1 / tan ² x = 1 / 2
tan ² x = 2
tan x = ± √2
x = 54.7°,125.3°, 234.7°, 305.3°