) You roll two dice, what is the probability that the sum of the dice is greater than 8?

Question

Last Question, I think! I seriously appreciate all of your help! Thank you for looking and answering!

Answer 1

P(9) = 4/36
P(10) = 3/36
P(11) = 2/36
P(12) = 1/36, so
P(>8) = 10/36 = 5/18

Answer 2

List the ordered pairs (1,1) to (6,6)
No. of ordered pairs where sum > 8 = 10
P(sum >10) = 10 / 36 = 5 / 18

Answer 3

sample space = { (1,1) (1,2) (1,3) (1,4) (1,5) (1.6) (2,1) (2,2) (2,3) (2,4) (2,5) (2,6) ( 3,1) (3,2) ( 3,3) (3,4) (3,5) (3,6) (4,1) (4,2) (4,3) ( 4,4) (4,5) (4,6) (5,1) (5,2) (5,3) (5,4) (5,5) (5,6) (6,1) (6,2) (6,3) (6,4) (6,5) (6,6) }

the events which will result in the sum of the dice being greater than 8 is { (3,6) (4,5) (4,6) (4,7) ( 5,4) ( 5,5) ( 5,6) (6,3) ( 6,4) ( 6,5) (6,6) }

11 * 1/36 = 11/36 = 0.3

Answer 4

Uummmm.....I am in the wrong category.....good luck with that question!