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An electron with a velocity of 3.00E6 m/s [horizontally] passes through two horiizontal parallel plates. The magnitude of the electirc field between the plates is 120 N/C. The plates are 4.0 cm across. Edge effects in the field are negligible.
I dunno where to begin, please help :(

2007-06-11 16:21:51 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

F acts over the length of plates
F=Eq
a= F/m
d=0.5at^2
t=S/Vh

d= (F/m) [S/Vh]^2
d= (Eq/m) [S/Vh]^2
E=120 N/C
q= 1.602 E-19 C
m=9.109 E–31 kg
S= 4.0 E-2 m
Vh=3.00E+6 m/s
This is without relativistic effect (this speed is about c/100).

2007-06-11 16:33:06 · answer #1 · answered by Edward 7 · 1 0

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