right answer= 10pts!!!....I promise!?

Question

Can anyone help with these, if you get the right answers first, you get 10 pts....I promise!!!

1. √4a^2+√9a^2

2. 10√y^5-√4y^5

Answer 1

Hi,


1. √4a^2+√9a^2 =

2a + 3a = 5a

2. 10√y^5-√4y^5 =

10y²√y.-.2y²√y =
.......__
8y²√y


I hope that helps!! :-)

Answer 2

Are you supposed to simplify them, and is 4a and 9a all under the radical or just the 4 and the 9?

Here

1. Since √4 = 2, and √9 = 3, then you have 2a + 3a=5a

2. Here, you treat everything under the radical as a variable.
Since you can factor out the 4 in √4y^5, you have:
10√y^5-2√y^5 since √y^5 is treated as a variable, simply subtract like terms. You are left with 8√y^5. Since y^5=yyyyy, √y^5=y^2√y. So your answer is 8y^2√y

Answer 3

1. √(4a^2) + √(9a^2)

First: express both radicals in lowest terms.

√(2*2*a*a) + √(3*3*a*a)
2a + 3a
5a

2. 10√(y^5) - √(4y^5)

First: express the radicals in lowest terms.

10√(y*y*y*y*y) - √(2*2*y*y*y*y*y)
(10)(y)(y)√y - (2)(y)(y)√y
10y^2 √y - 2y^2√y

Sec: combine the coefficients (because they have the same variable in the radical sign).

(10y^2 - 2y^2) √y
8y^2 √y

Answer 4

Question 1
Question is not clear without brackets.
Reading question as:-
(√4).a² + √9.a²
2a² + 3a² = 5a²
Question 2
Reading question as:-
10.y^(5/2) - √4.y^(5/2)
= 8.y^(5/2)
Conclusion
Use brackets to avoid needless work and wrong answers!

Answer 5

1. 5*lal l l is absolute value

2. 8√y^5

Answer 6

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Answer 7

1. 2a + 3a = 5a

2. (10y^2)√y -(2y^2)√y = (8y^2)√y

Answer 8

If you want to simplify them, here you are:

1. 5a
2. 8y^2 sqrt(y)

Answer 9

1.5a
2.8y^2 sqr y

Answer 10

1. 5a

2. 8y^2times sq.rt.(y)