how do you write this equation in vertex form?

Question

y= x^2 - 12x + 44

this is NOT my homework.its a review for a final and i need to know how to do it.

Answer 1

Complete the square.
y = x^2 - 12x + 44
y = (x^2 - 12x) + 44
Now take the coefficient of x. It is -12.
Divide this by 2. -12/2 = -6
Square it. (-6)^2 = 36
Add this number inside the parentheses, and subtract it outside the parentheses.
y = (x^2 - 12x + 36) + 44 - 36
y = (x-6)^2 + 8

This is vertex form.
The vertex is (6,8).

Answer 2

y= x^2 - 12x + 44

So complete the square in x^2

y = x^2 - 12x + 36 + 8

So y - 8 = (x - 6)^2

ie Y = X^2 where Y = y - 8 and X = x - 6

So this is a parabola of the y = x^2 family with vertex at (6, 8), axis vertical and concave up

Answer 3

y= x^2 - 12x + 44
Complete the square
y = x^2 -12x +36 +44-36
y = (x-6)^2 +8
The vertex is at (6,8)

Answer 4

y = x^2 - 12x + 44
y = (x - 6)^2 - 36 + 44
y = (x - 6)^2 + 8

Vertex: (6,8)