need help simplifying?

Question

Need help simplifying
(2d^4+2d^3-9d^2-3d+9) / 2d^2-3

Answer 1

By plugging in d=+/-sqrt(3/2) you will see that the denominator is a factor of the numerator


(2*d^2-3)(d^2+b*d+c)

2*d^4

2*b*d^3 b=1
(2*c-3)=-9
c=-3

so the final equation is

(d^2+d-3)

j

Answer 2

You would write it out like a long division problem. you need to change the divisor (outside number you are dividing by) to 2d^2 + 0d - 3.

It turns out to be d^2 + d - 3