1. Multiply: (6+i)(6-2i) 2. Solve: l5x+6l > 26?

Answer 1

1. (6+i)(6-2i) Use FOIL (First, Outside, Inside, Last)
(6+i)(6-2i)=
36 -12i + 6i -2i^2=
36 - 6i -2*-1=
36 - 6i + 2 =
38 - 6i.


2. |5x+6| > 26, so...
5x + 6 > 26 ; 5x + 6 < -26
5x > 20 ; 5x < -32
x > 4 ; x < -32/5.

Answer 2

1. (6+i)(6-2i) = 36-12i+6i-2(-1) = 38-6i

2. l5x+6l > 26
5x+6 > 26 or 5x+6 < -26
5x > 20 or 5x < -32
x > 4 or x < -6.4

Answer 3

6=654326 because of the fact a million=6, then 2=26 and 3=326. there's a trend right here: The type that comes previously the "equivalent image" turns into the type after the "equivalent image". Watch - 2=26 and 3=326 see how the two 2 and 3 become the 1st numbers? it relatively is the final answer plus the recent type. So 6=654326. Get it. it relatively is complicated to describe

Answer 4

1) ok, you foil it so you get (6+i)(6-2i) then 36-12i+6i-2i^2 so, 36-6i-2i^2

2) 5x+6>26 and 5x+6> -26
5x> 20 and 5x > -32
x> 4 and x> 6.4

hope that helps

Answer 5

Nobody ever wants to believe it, but you multiply complex numbers just --exactly-- the same as any other binomials.
(5+i)*(6-2i) = 30 - 10i + 6i -2i² = 30 - 4i + 2 = 32 - 4i

Doug

Answer 6

l5x+6l > 26

case 1:
5x + 6 > 26
x > 4

case 2:
5x + 6 < -26
x < -6.4

Answer 7

1. (6 +i)(6-2i) = 36 -12 i + 6i -2i^2 = 36 - 6 i +2 = 38 - 6i

2. does not make sense; did you miss something here

Answer 8

2. | 5x + 6 | > 26, gives us two pairs of equations:

5x + 6 > 26, , 5x > 20 thus x > 4 ;
-5x - 6 <= 26 , -5x <= 32 and x <= -5/32