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possible solutions....



a. (-1)<-2, 2, 1>

b. (-1/3)<-2, 2, 1>

c. (-2/9)<-2, 2, 1>

d. (-1/9)<-2, 2, 1>

e. <0, 0, 0>

f. (2/9)<-2, 2, 1)

g. (1/3)<-2, 2, 1>

h. <-2, 2, 1>

or is it none of these?

2007-06-11 09:05:43 · 1 answers · asked by chris 2 in Science & Mathematics Mathematics

1 answers

proj_b a = (a.b) b / ||b||^2
Now a.b = 4(-2) + 1(2) + 3(1) = 0. So proj_b a = <0, 0, 0>.

2007-06-11 21:39:32 · answer #1 · answered by Scarlet Manuka 7 · 0 0

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