please type the step by step answer
2007-06-11 08:27:10 · 6 answers · asked by MaeMae 1 in Science & Mathematics ➔ Mathematics
n²(n+1) - n(n² + 2) - n²
= n^3 + n² - n^3 -2n -n²
= (n^3 - n^3) + (n² - n²) -2n
= -2n
2007-06-11 08:31:43 · answer #1 · answered by MamaMia © 7 · 3⤊ 0⤋
If I am understanding your question properly we have:
n^2 * (n + 1) - n (n^2 + 2) - n^2 which equals
n^3 +n^2 - n^3 - 2n - n^2 which rearranged is:
n^3 - n^3 + n^2 - n^2 - 2n, thus leadig to
-2n
2007-06-11 08:34:51 · answer #2 · answered by Motown Robert 2 · 0⤊ 0⤋
n^2(n+1) -n(n^2 = 2) - n^2
n^3 + n^2 - n^3 - 2n - n^2
NB n^3 - n^3 = 0
& n^2 - n^2 = 0
thererfore we are left with - 2n
Ans = -2n
2007-06-15 08:22:14 · answer #3 · answered by lenpol7 7 · 0⤊ 0⤋
(n^2)(n+1) - n((n^2) + 2) - n^2
= n^3 + n^2 - n^3 - 2n - n^2
= -2n
2007-06-12 00:47:50 · answer #4 · answered by Kemmy 6 · 0⤊ 0⤋
n²(n+1) - n(n² + 2) - n²
= n³+ n² - n³ -2n -n²
= -2n
2007-06-11 08:32:35 · answer #5 · answered by sweet n simple 5 · 0⤊ 0⤋
i am no mathematician but isn't that just a complex was of Pythagoras
2007-06-11 08:30:53 · answer #6 · answered by vici 4 · 0⤊ 0⤋