putting x=6 and y=5 in equation
LHS is y
so LHS is 5
RHS
17x+6
17(6)+6
102 +6
108
so LHS(Left hand side ) is not equal to RHS(Right hand side)
so (6,5) is not a solution of y=17x+6
2007-06-11 08:10:23
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answer #1
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answered by sweet n simple 5
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Not even close. Substitute 5 instead y and 6 instead x in the equation:
5 = 17*6 + 6
5 = 102 + 6
5 = 108
and of course the above is false ==> the given point is not a solution to the given equation.
Regards
Tonio
Pd Some possible solutions (out of infinite ones) could be (1, 23), or (0, 6), or (-2, -28).
2007-06-11 15:11:54
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answer #2
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answered by Bertrando 4
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With problems like this, the thing in parenthesis represents a point where the first part is the x value and the second part is the y value. The y=17x+6 represents a line.
If a point is a solution, that means it lies on the line.
To check if this is true, just plug in the first value for x and the second value for y.
6=x
5=y
5=17(6)+6
5=102+6
5=108
Which is an untrue statement.
If it's untrue, the point is not a solution.
2007-06-11 15:12:14
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answer #3
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answered by Linduh. 3
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Substituting x by 6 in the equation:
y = 17 * 6 + 6
y = 108
Since y is supposed to be 5, (6, 5) isn't a solution.
Alternatively, substitute both x and y by their respective values:
5 = 17 * 6 + 6
5 = 108
Since we got different final values in each side, (6, 5) isn't a solution.
OTOH, (1, 23) is a solution:
23 = 17 * 1 + 6
23 = 23
2007-06-11 15:16:04
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answer #4
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answered by jcastro 6
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