English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

determine whether (6,5) is a solution

2007-06-11 08:02:55 · 4 answers · asked by sweetcherrypie20052006 1 in Science & Mathematics Mathematics

4 answers

putting x=6 and y=5 in equation

LHS is y

so LHS is 5

RHS
17x+6
17(6)+6
102 +6
108

so LHS(Left hand side ) is not equal to RHS(Right hand side)
so (6,5) is not a solution of y=17x+6

2007-06-11 08:10:23 · answer #1 · answered by sweet n simple 5 · 0 1

Not even close. Substitute 5 instead y and 6 instead x in the equation:
5 = 17*6 + 6
5 = 102 + 6
5 = 108
and of course the above is false ==> the given point is not a solution to the given equation.
Regards
Tonio
Pd Some possible solutions (out of infinite ones) could be (1, 23), or (0, 6), or (-2, -28).

2007-06-11 15:11:54 · answer #2 · answered by Bertrando 4 · 0 0

With problems like this, the thing in parenthesis represents a point where the first part is the x value and the second part is the y value. The y=17x+6 represents a line.
If a point is a solution, that means it lies on the line.
To check if this is true, just plug in the first value for x and the second value for y.

6=x
5=y

5=17(6)+6
5=102+6
5=108
Which is an untrue statement.
If it's untrue, the point is not a solution.

2007-06-11 15:12:14 · answer #3 · answered by Linduh. 3 · 0 0

Substituting x by 6 in the equation:

y = 17 * 6 + 6
y = 108

Since y is supposed to be 5, (6, 5) isn't a solution.

Alternatively, substitute both x and y by their respective values:

5 = 17 * 6 + 6
5 = 108

Since we got different final values in each side, (6, 5) isn't a solution.

OTOH, (1, 23) is a solution:
23 = 17 * 1 + 6
23 = 23

2007-06-11 15:16:04 · answer #4 · answered by jcastro 6 · 0 0

fedest.com, questions and answers