solve for x?

Question

i have no clue how to get rid of the "!" but i dont even know if i need to

(x-3)! / 5! = 4

Answer 1

First, I'd multiply both sides by 5!
(x-3)! = 5! * 4
(x-3)! = 1*2*3*4*5*4 = 480
Clearly, 480 is not any factorial: it's bigger than 5! but smaller than 6!.
Hence, there is no value of (x-3) such that (x-3)! = 480.
Hence, no value of x works. The equation has no solution.

Hope that helps!

Answer 2

First, I'd multiply both sides by 5!
(x-3)! = 5! * 4
(x-3)! = 1*2*3*4*5*4 = 480
Clearly, 480 is not any factorial: it's bigger than 5! but smaller than 6!.
Hence, there is no value of (x-3) such that (x-3)! = 480.
Hence, no value of x works. The equation has no solution.

Answer 3

First, change the denominator into a number.
5! = 120, so (x-3)!/120 = 4

Make the numerator a single variable x

x/ 120 = 4
x= 480
So, (x-3)! = 480

There is no number x such that (x-3)! = 480, so there is no answer for this question.