find the slope if it exsists of the line containing points
2007-06-11 07:41:10 · 6 answers · asked by jay_nikkiyost@sbcglobal.net 2 in Science & Mathematics ➔ Mathematics
slope = x-x1/y-y1
= 5-5/ [-3 - (-6)]
=0/-3
=0
2007-06-11 07:45:30 · answer #1 · answered by sweet n simple 5 · 0⤊ 5⤋
Slope = rise/run = (change in y)/(change in x).
Going from (5, -3) to (5, -6), y goes down by 3 and x doesn't change. So slope would be -3/0 - but since you're not allowed to divide by zero, the slope is undefined.
Answer: The slope is undefined.
The previous posts are wrong. To get a slope of 0, a line would have to be parallel to the x-axis. The line you're asking about is parallel to the y-axis.
2007-06-11 14:45:56 · answer #2 · answered by Bramblyspam 7 · 2⤊ 0⤋
Undefined or infinite. The line is vertical, as it runs through two points with the same x value.
The slope of a line between two points is determined by the difference in y divided by the difference in x. (-6 - -3)/(5 - 5) = -3/0. Anything divided by 0 is infinity.
2007-06-11 14:52:38 · answer #3 · answered by Master Maverick 6 · 1⤊ 0⤋
slope = (-6+3)/5-5 = -3/0 = no slope = vertical line
2007-06-11 14:47:38 · answer #4 · answered by Baysoc23 5 · 0⤊ 0⤋
The answer here is there is no slope or undefined. If you have two points, both of which has the same x coordinate, they lie on a vertical line. If two points had the same y-coordinate, it would be a horizontal line with slope zero.
2007-06-11 14:47:19 · answer #5 · answered by rcds23 6 · 0⤊ 0⤋
zero
2007-06-11 14:44:26 · answer #6 · answered by Anonymous · 1⤊ 4⤋