final question of the day....?

Question

This question seemed easy til i started to plug in the knowns and I got the wrong answer
A gymnast is swinging on a high bar. The distance between his waist and the bar is 0.8 m, as the drawing shows. At the top of the swing his speed is momentarily zero. Ignoring friction and treating the gymnast as if all his mass is located at his waist, find his speed at the bottom of the swing.

I manipulated the conservation of mechanical energy formulas and ended up with v=squareroot (2*g*h)<

Answer 1

If he's h above the bar at the top, he's -h above the bar at the bottom (h below). In other words, he drops 2h if h is the .8m. Or

v=sqrt(4gh)

Answer 2

That equation should be right. But make sure you use the right h. The difference in hight of the waist from top to bottom is 1.6m (it is 0.8 above the bar when at the top, and 0.8 below the bar at bottom).

Answer 3

Gymnast Drawing

Answer 4

the answer I got was blue, is that correct?