integration of 1/(x^2) ?

Question

what are the steps?

Answer 1

1/(x^2) = x^-2
You should be able to do it easy in that form.

Answer 2

integration of x to the power of -2
=-1/x

Answer 3

Since this can be written as x^(-2), and the exponent isn't equal to -1, we can integrate using the standard form. The answer would be -x^(-1).

Answer 4

First, rewrite the integral to read x^-2

Remember the formula for integrating a polynomial function? It is:

x^n+1/n+1 +C, with C bieng the constant of integration.

Now use your formula to evaluate the integral:

Add 1 to the exponent to get: x^-1/-1

Now simplify to get you final answer:

-1/x+C

Hope this helps.

Answer 5

since x^2 is in the denominator it is to the power of minus 1,
add 1 to the power and divide by the new power,
namely x^-2 add 1 equals x^-1 and divide by -1
answer is -1/x

Answer 6

simply (-1/x) that because 1/(x^2) means x^(-2) by increasing the power by one and then dividing on the new power (-1)
you'll have the answer "POWERS RULE OF INTEGRATION"
Ahmed Khaled Swelam

Answer 7

What precisely is it which you rather want? Do you basically want the respond? right here it incredibly is: ? dx/(one million + x²) = tan?¹x + C or you you prefer to be certain the way it incredibly is derived? enable x = tan ?, so dx = sec²? d? and take it from there ... in view which you probably did no longer incredibly ask, I basically gave you a splash. attempt asking in an (very almost) finished sentence.

Answer 8

∫ x^-2 dx
= x^-1 / -1

= -1/x

Answer 9

easier if you write it as x^(-2)

Then you can see that it is clearly -x^(-1) or -1/x

Answer 10

we use the formula
INT{x^n}dx=x^(n+1)/(n+1).

INT{1/x^2}dx
=INT{x^(-2)}dx
=x^(-2+1)/(-2+1)
=x^(-1)/(-1)
= -1/x