An 800w,220V kettle and three 100W,220V bulbs are connected in parallel across a 220V source.The current drawn from the source-
1. 6.9A
2. 5.5A
3. 5.0A
4. .15A
2007-06-11 03:50:10 · 4 answers · asked by godisgreat 1 in Science & Mathematics ➔ Physics
W / V = A
800w / 220v = 3.6363636a
100w / 220v = 0.4545454a
100w / 220v = 0.4545454a
100w / 220v = 0.4545454a
Now add up the currents because they are in parallel:
[ 5 amps ]
2007-06-11 03:56:26 · answer #1 · answered by ? 5 · 0⤊ 1⤋
It would be cheating to give you the answer, but this will get you started:
1. Because they're connected in parallel, all 4 devices receive the full 220V. That means they'll all run at their full power (full wattage rating).
2. Figure out how much total power is used by all 4 devices.
3. Use the formula that relates current to power and voltage.
2007-06-11 11:00:27 · answer #2 · answered by RickB 7 · 0⤊ 0⤋
P = IV
Total Power is 1100 W.
1100 W = I * 220V
I = 1100/220 = 5.0
2007-06-11 11:00:44 · answer #3 · answered by tbolling2 4 · 0⤊ 0⤋
Power (watts) = current(amps) x voltage (volts). Calculate the current for each appliance. Because the appliances are in parallel, the currents are additive.
2007-06-11 10:58:54 · answer #4 · answered by Scott H 3 · 0⤊ 0⤋