2007-06-11 03:50:09 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
AB=sqrt(64+4+1)=sqrt(69)=8.31
2007-06-11 03:57:16 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Distance
= sqrt[(-7-1)^2 + (3-5)^2 + (2-1)^2]
= sqrt[64 + 4 + 1]
= sqrt(69)
= 8.31
2007-06-11 05:52:21 · answer #2 · answered by Kemmy 6 · 0⤊ 0⤋
(x, y, z)
to determine distance, you use the equation:
√ [ ( xB - xA)^2 + ( yB - yA)^2 + ( zB - zA)^2 ]
so
√ [ ( 1 + 7)^2 + ( 5 - 3)^2 + ( 1 - 2)^2 ]
√ [ 8^2 + 2^2 + (-1)^2 ]
√ (64 + 4 + 1)
√ 69
8.31
2007-06-11 04:00:06 · answer #3 · answered by regreg 3 · 0⤊ 0⤋
Plug the points into the 3D distance formula
d = sqrt((X2-X1)^2 + (Y2-Y1)^2 + (Z2-Z1)^2)
2007-06-11 03:56:36 · answer #4 · answered by ≈ nohglf 7 · 0⤊ 0⤋
listen to find out distance between two points (x,y,z) and (a,b,c)
put the formula
squareroot[(x-a)^2+(y-b)^2+(z-c)^2]
put values get ans.............
2007-06-11 03:57:38 · answer #5 · answered by Anonymous · 0⤊ 0⤋