Given A(1, 2) and B(5, 5), find the magnitude of vector AB?

Answer 1

Magnitude of a vector with two points is given by (x2 - x1)^2 + (y2 - y1)^2

So, in this case, we write:

x2 - x1 = 5 -1 = 4 and its square will be 16.

y2 - y1 = 5 - 2 = 3 and its square will be 9

Adding them, we get 25 and taking square root, we get magnitude of the vector as 5.

Answer 2

Vector AB = (4 3)
Magnitude of AB = √(4² + 3²)
Magnitude of AB = 5

Answer 3

magnitude is :
square root( ( y2-y1)^2 + (x2-x1)^2)

whre y1,y2 are the first and second y co-ordinates
and x1,x2 are the first and second x co-ordinates

hence magnitude here is root( 9 + 16) = 5 !

Answer 4

the vector is Vab = B-A = (5-1,5-2) = [4,3]
so magnitude is ||Vab|| = d[4,3] = sqrt(3^2 + 4^2) = 5