Help - Find the solutions to the equation: (x-16)^2=4?

Question

Math is not my best subject and is holding up me getting my degree. This equation is x-16 squared=4

Answer 1

(x-16)^2=4

(x-16)^2=2^2

x-16 = 2 => 18
x-16 = -2 => 14

Answer 2

permit y = x + 2 question selection a million : For this equation y^2 + 7*y + 12 = 0 , answer right here questions : A. Use winding up the sq. to discover the basis of the equation ! answer selection a million : The equation y^2 + 7*y + 12 = 0 is already in a*x^2+b*x+c=0 form. In that form, we are able to relatively derive that the fee of a = a million, b = 7, c = 12. 1A. Use winding up the sq. to discover the basis of the equation ! y^2 + 7*y + 12 = 0 ,divide the two area with a million Then we get y^2 + 7*y + 12 = 0 , meaning that the coefficient of y is 7 we would desire to apply the certainty that ( y + q )^2 = y^2 + 2*q*y + q^2 , and assume that q = 7/2 = 3.5 next, we would desire to split the consistent to form y^2 + 7*y + 12.25 - 0.25 = 0 So we are able to get ( y + 3.5 )^2 - 0.25 = 0 that's the comparable with (( y + 3.5 ) - 0.5 ) * (( y + 3.5 ) + 0.5 ) = 0 that's the comparable with ( y + 3.5 - 0.5 ) * ( y + 3.5 + 0.5 ) = 0 Do the addition/subtraction, and we get ( y + 3 ) * ( y + 4 ) = 0 So we've been given the solutions as y1 = -3 and y2 = -4 Now on the grounds that y=x+2 this means that x=y-2 x1= -3-2 = -5 x2= -4-2 = -6

Answer 3

Well, you may not deserve a degree if you can't do this. However, here you go...

Square root both sides

√((x-16)^2) = √4
(x - 16) = ±2

==> note that you get a positive or negative 2 w/ the square root, so you essentially have two equations now:

(x - 16) = -2 AND (x - 16) = 2

So, solve each one by adding 16 to both sides:

x - 16 = -2
x = 14

x - 16 = 2
x = 18

So, you have two solutions, x = 14 and x = 18.

Answer 4

You have something in parentheses, squared, which equals 4. Well, what number times itself equals 4. 2^2 = 4, but also (-2)^2 = 4. That tells me that the stuff in parentheses has to equal 2 or -2.
So, if x - 16 = 2
then x = 18

If x - 16 = -2,
then x = 14

Answer 5

(x - 16)(x - 16) = 4

x^2 - 32x + 256 = 4

x^2 - 32x + 252 = 0

(x - 14)(x - 18) = 0

x = 14 or x = 18

Despite the thumbs down, *this* is the correct method. The others are taking shortcuts because the sq.rt. of 4 is easy. What if you had the same equation with a number that didn't have a rational sq.rt (eg 17)?

Answer 6

You must use the process Foil (First Inside Outside Last) to solve this equation.
(X-16)^2=4
(X-16)(X-16)=4
X^2-16X-16X+256=4 Simplify
X^2-32X+256=4
-256 -256
Answer: X^2-32X=-252

Answer 7

(x-16)^2 = 4
therefore
x-16 = 2 => x = 18
or
x-16 = -2 => x = 14

Answer 8

(x-16)^2=4

Expand

x² - 32x +256 = 4

Subtract 4 from both sides

x² - 32x +252 = 0

(x - 14)(x - 18) = 0

x = 14, x = 18

or, an easier route

(x - 16)² = 4

Take the square root of both sides

x - 16 = ±2

x = 14, x = 18
.

Answer 9

you have got to be kidding me. This is Junior high school level math. Work backwards buddy. Opposite of square is the square root. Add sixteen to both sides. I could give you the answer but without showing the mathematical proof your teacher will still mark it as wrong.

Answer 10

(x-16)^2=4
=> (x-16)^2-4=0
=.(x-16)^2-(2)^2=0
=>(x-16+2)(x-16-2)=0
=>(x-14)(x-18)=0
Therefore x= 14 or 18