Algebra
2007-06-11 02:28:23 · 10 answers · asked by virtuegirl 1 in Science & Mathematics ➔ Mathematics
7x+2x>21-3
9x>18
x>2
2007-06-11 02:38:03 · answer #1 · answered by ђermiona 6 · 0⤊ 0⤋
7x + 2x > 21 - 3
9x > 18
x > 18/9
x > 2
x = 2
2007-06-11 09:38:18 · answer #2 · answered by zaheen797 3 · 0⤊ 0⤋
7x + 2x > 21 - 3
Solve as you would an equation, combine terms.
9x > 18
Divide thru by 9.
x > 2
.
2007-06-11 09:36:30 · answer #3 · answered by Robert L 7 · 0⤊ 0⤋
just simplify the equation. 7x and 2x amounts to 9x; 21-3 results to 18. Then restate the equation to the results of simplifying process, that is 9x > 18.
2007-06-15 07:23:19 · answer #4 · answered by Jun Agruda 7 · 2⤊ 0⤋
compute for the value on each side
7x+2x > 21-3
therefore
9x > 18
then divide each side with the common denominator which is 9
9x/9 > 18/9
so you get
x > 2
therefore, the value of x is 3 and above
2007-06-11 09:51:47 · answer #5 · answered by capricorn 1 · 0⤊ 0⤋
7x+2x>21-3
x(7+2)>18
x(9)>18
9x>18
9x>9*2
divide both sides by 9
x>2
2007-06-11 09:43:45 · answer #6 · answered by Bored 3 · 0⤊ 0⤋
9x > 18
x > 2
2007-06-11 09:42:26 · answer #7 · answered by Como 7 · 0⤊ 0⤋
add and subtract like terms...
9x>18
divide 9 by 18...
9x>18
--- -----
9 9
x>2
hope i helped! i took algebra 1 this past year!
2007-06-11 09:37:32 · answer #8 · answered by Addie 4 · 0⤊ 0⤋
Sum/subtract the terms at each side:
9x > 18
Divide each side by 9:
x>2
The End. :)
2007-06-11 09:32:03 · answer #9 · answered by Jhack 3 · 0⤊ 0⤋
x is equivalent or more than 3..
2007-06-11 09:33:10 · answer #10 · answered by idlevil_73 3 · 0⤊ 0⤋