2007-06-11 01:34:04 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
6x² - 7x - 5 = 0
The middle term is - 7x
Find the sum of the middle term
Multiply the first term 6 times the last term 5 equals 30 and factor
factors of 30
1 x 30
2 x 15
3 x 10 . . .<=. .use these factors
5 x 6
+ 3 and - 10 satisfy the sum of the middle term
insert + 3x and - 10x into the equation
6x² - 7x - 5 = 0
6x² + 3x - 10x - 5 = 0
3x(2x + 1) - 5(2x + 1) = 0
(3x - 5)(2x + 1)
- - - - - - - - -s-
2007-06-11 02:06:18 · answer #1 · answered by SAMUEL D 7 · 0⤊ 1⤋
(3x - 5).(2x + 1)
Check
3x.(2x + 1) - 5.(2x + 1)
= 6x² + 3x - 10x - 5
= 6x² - 7x - 5 as required.
2007-06-11 09:24:01 · answer #2 · answered by Como 7 · 0⤊ 1⤋
6x^2-7x-5=6x^2-10x+3x-5=2x(3x-5)+1(3x-5).
=(3x-5)(2x+1).
its zeros are:-1/2,5/3 answer
2007-06-11 08:53:58 · answer #3 · answered by Anonymous · 0⤊ 1⤋
(3x - 5)(2x + 1)
2007-06-11 08:40:41 · answer #4 · answered by yeeeehaw 5 · 0⤊ 1⤋