when a charge of 4.2 x 10^-5 C is added to a capacitor, the potential difference increases from 10.6 V to 16.2

Question

the potential difference increases from 10.6 V to 16.2 V . what is the capacitance of the capacitor?

A 1.3
B 2.4
C 7.5
D 9.1

Answer 1

Strictly speaking, answer 1 is correct. A fuller explanation:
Charge Q = C * V, so C = Q / V, V in this case being the voltage change, 5.6 v.
4.2E-5 / 5.6 = 7.5E-6, so the capacitance is 7.5 uF. Could be that you left out the units in the answers?

Answer 2

none of the above