What is the buoyant force on the object ?
2007-06-10 21:05:22 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Ok first you need the density of the object which is:
8.3 / 0.00086 = 9651 kg/m-3
Which means it would sink like a stone and no buoyant force would be apparent.
2007-06-10 21:15:17 · answer #1 · answered by nkellingley@btinternet.com 5 · 0⤊ 0⤋
The weight of water displaced is 0.86*10^-3 m^3 * 10^6 g / m^3 = 0.86*10^3 g = 0.86 kgwt. That is the bouyant force.
2007-06-10 21:14:34 · answer #2 · answered by gp4rts 7 · 0⤊ 0⤋
Volume x dnsity of water x g.
0.86 x 10^-3 x 10 ^3 x 9.8 =8.426 N
2007-06-10 21:13:53 · answer #3 · answered by Pearlsawme 7 · 0⤊ 0⤋
appears like UR into great/small selection calculations :>) a million m = 10² cm and a million m³ = (10² cm)³ = 10E6 cm³ so 10E6(10E-3) = 100E3 = 10E4 kg ANS (a) a million µm = 10E-6 m quantity of a sphere = 4/3?R³ = 4/3?(5E-6)³ = 4/3?(125E-18) = 524E-18 m³ estimate of mass of a cellular (sphere of water) = 524E-18(10E4) = 5240E-14 kg ANS (b) {i don't see why this estimation would be unable to be with the completed cellular being seen water because of the fact the the rest 2% has to have some density - so estimate THAT to be water too} How approximately U attempting a number of those?
2016-11-10 02:03:39 · answer #4 · answered by ? 4 · 0⤊ 0⤋
B.F. = (0.86*10^-3 m^3)(1 kg/m^3)(9.80662 m/s^2) = 0.0084336932 N
2007-06-10 21:24:23 · answer #5 · answered by Helmut 7 · 0⤊ 0⤋