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supplies 2.70x10^2 J of energy in 20.0 s?

2007-06-10 18:01:56 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

P = E/t = V^2/R
R = V^2t/E
R = 20*14^2/270
R = 14.5 Ω

2007-06-10 21:42:05 · answer #1 · answered by Helmut 7 · 0 0

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