i really need your help on this?

Question

Find the FACTORS of the polynomial: x4 - x3 - 19x2 - 11x + 30 = 0

what are the FACTORS in the form (ax+b)??

please help me ~!!

Answer 1

x^4 - x^3 - 19x^2 - 11x + 30 = 0

by trial,
let x=1
x^4 - x^3 - 19x^2 - 11x + 30
=1^4 - 1^3 - 19(1)^2 -11(1) +30
=0

so x=1 is one of the factors

let x=-2
x^4 - x^3 - 19x^2 - 11x + 30
=(-2)^4 - (-2)^3 - 19(-2)^2 -11(-2) +30
=0

so x=-2 is another factor

x4 - x3 - 19x2 - 11x + 30
=(x+2)(x-1)Q(x)
=(x^2+x-2)(x^2-2x-15)
=(x+2)(x-1)(x-5)(x+3)

Answer 2

The factors are (x-5)(x-1)(x+2)(x+4)

Answer 3

The answer already given cannot be correct, since 5x1x4x2=40, not 30

the answer is the factors are:
(x-1) , (x+2) , (x+3) and (x-5)

Answer 4

(x - 5)(x - 1)(x + 2)(x + 3)

Answer 5

x^4 - x^3 - 19x^2 - 11x + 30 = 0
x^3(x-1)-19x^2+19x-30x+30=0
or x^3(x-1)-19x(x-1)-30(x-1)=0
or (x-1)(x^3-19x-30)=0
or (x-1)(x^3+2x^2-2x^2-4x-15x-30)=0

or(x-1){x^2(x+2)-2x(x+2)-15(x+2)}=0
or(x-1)(x+2)(x^2-2x-15)=0
or(x-1)(x+2){x^2-5x+3x-15}=0
or(x-1)(x+2){x(x-5)+3(x-5)}=0
0r(x-1)(x+2)(x+3)(x-5)=0